<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Converting a IEnumerator to IEnumerator&lt;T&gt;</title>
	<atom:link href="http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/</link>
	<description>Daniel Hoelbling talks about .NET</description>
	<lastBuildDate>Sun, 14 Mar 2010 16:22:22 +0100</lastBuildDate>
	<generator>http://wordpress.org/?v=abc</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: Daniel Hölbling</title>
		<link>http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/comment-page-1/#comment-3377</link>
		<dc:creator>Daniel Hölbling</dc:creator>
		<pubDate>Mon, 26 Oct 2009 21:53:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/#comment-3377</guid>
		<description>Oh thanks for the tip.&lt;br&gt;I didn&#039;t look into 3.5 solutions since that particular problem cropped up in a 2.0 solution.. &lt;br&gt;&lt;br&gt;greetings Daniel</description>
		<content:encoded><![CDATA[<p>Oh thanks for the tip.<br />I didn&#39;t look into 3.5 solutions since that particular problem cropped up in a 2.0 solution.. </p>
<p>greetings Daniel</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: JulianBirch</title>
		<link>http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/comment-page-1/#comment-3376</link>
		<dc:creator>JulianBirch</dc:creator>
		<pubDate>Mon, 26 Oct 2009 20:42:20 +0000</pubDate>
		<guid isPermaLink="false">http://www.tigraine.at/2009/10/11/converting-a-ienumerator-to-ienumeratort/#comment-3376</guid>
		<description>If you&#039;re on 3.5, you can actually call Cast on an untyped enumerator.&lt;br&gt;&lt;br&gt;So you could write &lt;br&gt;&lt;br&gt;return untypedEnumerator.Cast&lt;T&gt;();</description>
		<content:encoded><![CDATA[<p>If you&#39;re on 3.5, you can actually call Cast on an untyped enumerator.</p>
<p>So you could write </p>
<p>return untypedEnumerator.Cast&lt;T&gt;();</p>
]]></content:encoded>
	</item>
</channel>
</rss>
